x^2-4x-345=0

Solution for x^2-4x-345=0 equation:

x^2-4x-345=0

a = 1; b = -4; c = -345;
Δ = b2-4ac
Δ = -42-4·1·(-345)
Δ = 1396
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1396}=\sqrt{4*349}=\sqrt{4}*\sqrt{349}=2\sqrt{349}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{349}}{2*1}=\frac{4-2\sqrt{349}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{349}}{2*1}=\frac{4+2\sqrt{349}}{2}
$